Write an equation in standard form for a line passing through (3, -5) and is perpendicular to the line y = 3x - 6

tophergopher3wo

tophergopher3wo

Answered question

2022-09-12

Write an equation in standard form for a line passing through (3, -5) and is perpendicular to the line y = 3x - 6

Answer & Explanation

enreciarpv

enreciarpv

Beginner2022-09-13Added 18 answers

You may use the general relationship:
y - y 0 = m ( x - x 0 )
Where x 0 , y 0 are the coordinates of your point (3,−5) and m is the slope.Now, for your line to be perpendicular to the given one it needs to have a slope: m = - 1 m 1 where m 1 is the slope of your given line (i.e., m 1 = 3 , the coefficient of x in y=3x−6), and m = - 1 3
So finally:
y - ( - 5 ) = - 1 3 ( x - 3 )

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