A farmer bought 100 ha of land, part at $1850 per hectare and part at $2250 paying for the whole $215000. How much land was there in each part? Round only final answers. Round to the whole. ha at $1850/ha ha at

Charlie Conner

Charlie Conner

Answered question

2022-09-27

A farmer bought 100 ha of land, part at $1850 per hectare and part at $2250 paying for the whole $215000. How much land was there in each part? Round only final answers. Round to the whole. ha at $1850/ha ha at

Answer & Explanation

Phoenix Owen

Phoenix Owen

Beginner2022-09-28Added 6 answers

Let x be the number of hectares purchased for $2250. Since we know the total number of hectares purchased was 100, this leaves (100−x) hectares remaining.
What you're trying to find is x. We know the total cost of the land was $215,000, so if you take the number of hectares purchased for $2250 (x) and multiply it by the price (2250), then add that to the remaining hectares that you know were purchased for $1850, you get the following equation:
2250 x + 1850 ( 100 - x ) = 215000
2250 x + 185000 - 1850 x = 215000 Distribute the 1850
400 x = 30000 Combine like terms
x = 75 Divide by 400
This means that the number of hectares purchased at $2250 was 75 and the remaining number of hectares (100−75or25) was purchased at 1850.

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