rancuri5a

2022-10-03

Write an equation for the line parallel to 2x−y=4 that goes through (8, -12) in slope-intercept form

Quinn Alvarez

Beginner2022-10-04Added 13 answers

We first write 2x−y=4 in slope-intercept form:

$2x-y=4\to$ add y and subtract 4 on both sides

$2x-4=y\to y=2x-4$ where 2 is the slope

Now fill in (8,−12) (b is the new y-intercept)

$y=2x+b\to -12=2\cdot 8+b\to b=-28$

So the new equation is: $y=2x-28$

$2x-y=4\to$ add y and subtract 4 on both sides

$2x-4=y\to y=2x-4$ where 2 is the slope

Now fill in (8,−12) (b is the new y-intercept)

$y=2x+b\to -12=2\cdot 8+b\to b=-28$

So the new equation is: $y=2x-28$

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