dannyboi2006tk

2022-09-30

Find the slope of any line perpendicular to the line passing through (−3,−4) and (−2,−3)

xgirlrogueim

Beginner2022-10-01Added 13 answers

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Given points (−3,−4),(−2,−3)

$\text{Slope of given line}\phantom{\rule{1ex}{0ex}}m=\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}$

$m=\frac{-3+4}{-2+3}=1$

$\text{Slope of perpendicular line}\phantom{\rule{1ex}{0ex}}{m}_{1}=-\frac{1}{m}=-1$

$\text{Slope of given line}\phantom{\rule{1ex}{0ex}}m=\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}$

$m=\frac{-3+4}{-2+3}=1$

$\text{Slope of perpendicular line}\phantom{\rule{1ex}{0ex}}{m}_{1}=-\frac{1}{m}=-1$

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