aphathalo

2022-10-06

Write equations of a line parallel to x−y−12=0 that passes through (2, -5)

antidootnw

Beginner2022-10-07Added 10 answers

Re-write the equation x−y−12=0 into a slope-intercept form y=mx+b

y=(1)x−12

So we are looking for line with slope of 1 through the point (2,−5)

This can easily be achieved using the slope-point form of the equation: $(y-{y}_{1})=m(x-{x}_{1})$

In this case ${y}_{1}=(-5)$, ${x}_{1}=2$, and m=1

So our equation is

$y+5=\left(1\right)(x-2)$

which simplifies as

$y=x-7$

y=(1)x−12

So we are looking for line with slope of 1 through the point (2,−5)

This can easily be achieved using the slope-point form of the equation: $(y-{y}_{1})=m(x-{x}_{1})$

In this case ${y}_{1}=(-5)$, ${x}_{1}=2$, and m=1

So our equation is

$y+5=\left(1\right)(x-2)$

which simplifies as

$y=x-7$

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