fofopausiomiava

2022-09-06

Find the equation of the line that passes through the point (0,2) and perpendicular to the line x-y=6

Rihanna Blanchard

Beginner2022-09-07Added 13 answers

Let,the equation of the line be y=mx+c where, m is the slope and c is the Y intercept.

now,slope of the equation x−y=6 or y=x−6 is 1

We know that for two lines to be mutually perpendicular,their product of slope will have to be −1

So,m*1=−1

or, m=−1

So,the equation becomes, y=−x+c

Now,given the line passes through (0,2)

So,putting the values we get,

2=0+c

So,the equation of the line is, y=−x+2

or, x+y=2

now,slope of the equation x−y=6 or y=x−6 is 1

We know that for two lines to be mutually perpendicular,their product of slope will have to be −1

So,m*1=−1

or, m=−1

So,the equation becomes, y=−x+c

Now,given the line passes through (0,2)

So,putting the values we get,

2=0+c

So,the equation of the line is, y=−x+2

or, x+y=2

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