Find the equation of the line perpendicular to y=−7x that passes through (6,−1)

Nathanial Levine

Nathanial Levine

Answered question

2022-10-08

Find the equation of the line perpendicular to y=−7x that passes through (6,−1)

Answer & Explanation

Kaitlyn Levine

Kaitlyn Levine

Beginner2022-10-09Added 12 answers

Slope of the line L:y=−7x is −7.
Knowing that, the Product of Slopes of mutually lines is
−1, the slope of the reqd. line ( - 1 - 7 ) = 1 7 .
Also, the reqd. line passes thro. the pt. (6,−1.)
Therefore, by the Slope-Point Form, the eqn. of reqd. line is,
y - ( - 1 ) = 1 7 ( x - 6 ) , i . e . , 7 y + 7 = x - 6 .
x - 7 y - 13 = 0 .

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