garnirativ8

2022-10-07

A corner store sells two kinds of baked goods: cakes and pies. A cake costs $14 and a pie costs $8. In one day, the store sold 12 baked goods for a total of $144. Tell me how many cakes did they sell

Samantha Braun

Beginner2022-10-08Added 9 answers

Out of 12 baked goods sold , let the number of cakes sold

be x in number and pies sold were 12−x in number.

Total sell was $144 , 1 cake costs $14 and 1 pie costs

$\$8\therefore 14\cdot x+(12-x)\cdot 8=144\phantom{\rule{1ex}{0ex}}\text{or}\phantom{\rule{1ex}{0ex}}14x-8x=144-96}$ or

$6x=48\therefore x=8$

be x in number and pies sold were 12−x in number.

Total sell was $144 , 1 cake costs $14 and 1 pie costs

$\$8\therefore 14\cdot x+(12-x)\cdot 8=144\phantom{\rule{1ex}{0ex}}\text{or}\phantom{\rule{1ex}{0ex}}14x-8x=144-96}$ or

$6x=48\therefore x=8$

pokvarilaap

Beginner2022-10-09Added 3 answers

You can use two variables.

Let the number of cakes be x and the number of pies be y

If 12 baked goods were sold:

x+y=12 -> x=(12−y)

Using the price of each we can write the equation:

14x+8y=144

14(12−y)+8y=144

168−14y+8y=144

168−144=6y

24=6y

4=y

4 pies were sold and 8 cakes were sold.

Let the number of cakes be x and the number of pies be y

If 12 baked goods were sold:

x+y=12 -> x=(12−y)

Using the price of each we can write the equation:

14x+8y=144

14(12−y)+8y=144

168−14y+8y=144

168−144=6y

24=6y

4=y

4 pies were sold and 8 cakes were sold.

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