st3he1d0t

2022-09-05

FInd the integers if the sum of three consecutive even integers is 66

Matthew Benton

Beginner2022-09-06Added 9 answers

You have to 'jump' an odd number to get to the next even number. So even numbers occur every second place (counting in 2's)

Set the first even number as n

Then the second is n+2

The third is n+4

Subtract 6 from both sides

3n=60

Divide both sides by 3

n=20

So the three numbers are: 20;22;24

Set the first even number as n

Then the second is n+2

The third is n+4

Subtract 6 from both sides

3n=60

Divide both sides by 3

n=20

So the three numbers are: 20;22;24

Kwenze0l

Beginner2022-09-07Added 2 answers

Take the first integer as x. Since we are talking about the next even integer, it will come when you add two to x.

For example, let's say that you have 2 as the value of x. The next even integer is 4, which is x+2, and the next is 6, which is x+4.

So eventually, the equation is

(x)+(x+2)+(x+4)=66

3x+6=66

3x=66−6

3x=60

x=60/3

x=20

So

x=20

x+2=22

x+4=24

For example, let's say that you have 2 as the value of x. The next even integer is 4, which is x+2, and the next is 6, which is x+4.

So eventually, the equation is

(x)+(x+2)+(x+4)=66

3x+6=66

3x=66−6

3x=60

x=60/3

x=20

So

x=20

x+2=22

x+4=24

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