Buszmenan

2022-10-09

Write an equation of a line passing through (0, 4), perpendicular to y=x

recepiamsb

Beginner2022-10-10Added 9 answers

We have been given one point (0,4) and (indirectly) the slope.

It lines are perpendicular, then one slope is the negative reciprocal of the other.

In y=x, it is actually y=+1x so the slope, m=1

The slope perpendicular to this will be m=−1

The point we have been given is a specific point:

It is the y-intercept, c=4, so we have everything we need to write the equation of the line in the form y=mc+c

y=−x+4

It lines are perpendicular, then one slope is the negative reciprocal of the other.

In y=x, it is actually y=+1x so the slope, m=1

The slope perpendicular to this will be m=−1

The point we have been given is a specific point:

It is the y-intercept, c=4, so we have everything we need to write the equation of the line in the form y=mc+c

y=−x+4

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V=??

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a) $f(x)=-3x+4$

b) $f\left(x\right)=-3{x}^{2}+7$

c) $f(x)=\frac{x+1}{x+2}$

?

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B)Parallelogram;

C)Kite;

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$C=2\times {10}^{3}$,

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