Haiden Meyer

2022-10-08

Write an equation in slope-intercept form for a line that is parallel to the given line y = -1/4x + 9 and passes through the given point(-4, 4)

Joel Reese

Beginner2022-10-09Added 17 answers

Since the line

$y=-\frac{1}{4}x+9$

is already in slope-intercept form, we know that the slope of the line is $-\frac{1}{4}$.

Two lines are parallel if they have the same slope, so our line will also have slope $-\frac{1}{4}$, which means that it has equation like

$y=-\frac{1}{4}x+q$

Let's impose the passage through (−4,4):

$4=-\frac{1}{4}\cdot (-4)+q\iff 4=1+q\iff q=3$

So, the equation is

$y=-\frac{1}{4}x+3$

$y=-\frac{1}{4}x+9$

is already in slope-intercept form, we know that the slope of the line is $-\frac{1}{4}$.

Two lines are parallel if they have the same slope, so our line will also have slope $-\frac{1}{4}$, which means that it has equation like

$y=-\frac{1}{4}x+q$

Let's impose the passage through (−4,4):

$4=-\frac{1}{4}\cdot (-4)+q\iff 4=1+q\iff q=3$

So, the equation is

$y=-\frac{1}{4}x+3$

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