Kwenze0l

2022-09-09

Find the slope that is perpendicular to the line 4x−3y=−24

Joaquin Cisneros

Beginner2022-09-10Added 4 answers

This equation is in Standard Form for a linear equation. The standard form of a linear equation is: Ax+By=C

Where, if at all possible, A, B, and Care integers, and A is non-negative, and, A, B, and C have no common factors other than 1

The slope of an equation in standard form is: $m=-\frac{{A}}{{B}}$

Our equation is: 4x−3y=−24

Therefore the slope of the line in the equation is:

$m=\frac{-{4}}{{-3}}=\frac{4}{3}$

Let's call the slope of a line perpendicular to the line in the problem:

$m}_{p$

The formula for a perpendicular line is:

$m}_{p}=-\frac{1}{m$

Substituting the slope we calculated for m gives:

$m}_{p}=-\frac{1}{\frac{4}{3}}=-\frac{3}{4$

Where, if at all possible, A, B, and Care integers, and A is non-negative, and, A, B, and C have no common factors other than 1

The slope of an equation in standard form is: $m=-\frac{{A}}{{B}}$

Our equation is: 4x−3y=−24

Therefore the slope of the line in the equation is:

$m=\frac{-{4}}{{-3}}=\frac{4}{3}$

Let's call the slope of a line perpendicular to the line in the problem:

$m}_{p$

The formula for a perpendicular line is:

$m}_{p}=-\frac{1}{m$

Substituting the slope we calculated for m gives:

$m}_{p}=-\frac{1}{\frac{4}{3}}=-\frac{3}{4$

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