s2vunov

2022-10-11

How do you write the equation in point slope form given $m=\frac{1}{2}$ and point (7,−6)?

Marshall Horne

Beginner2022-10-12Added 8 answers

There are several ways of indicating the equation of a straight line:

There are all interchangeable.

ax+by+c=0 is general form

ax+by=c is standard form

y=mx+c is slope-intercept form

$y-{y}_{1}=m(x-{x}_{1})$ is point slope form $\leftarrow$ use this one

$m=\frac{1}{2}\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}(7,-6)$

$y-(-6)=\frac{1}{2}(x-7)$

$y+6=\frac{1}{2}(x-7)\phantom{\rule{1ex}{0ex}}\text{}\phantom{\rule{1ex}{0ex}}$ is the required form.

There are all interchangeable.

ax+by+c=0 is general form

ax+by=c is standard form

y=mx+c is slope-intercept form

$y-{y}_{1}=m(x-{x}_{1})$ is point slope form $\leftarrow$ use this one

$m=\frac{1}{2}\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}(7,-6)$

$y-(-6)=\frac{1}{2}(x-7)$

$y+6=\frac{1}{2}(x-7)\phantom{\rule{1ex}{0ex}}\text{}\phantom{\rule{1ex}{0ex}}$ is the required form.

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V=??

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a) $f(x)=-3x+4$

b) $f\left(x\right)=-3{x}^{2}+7$

c) $f(x)=\frac{x+1}{x+2}$

?

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B)Parallelogram;

C)Kite;

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$B=1.4\times {10}^{-1}$,

$C=2\times {10}^{3}$,

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B)4;

C)6;

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