jamstavajo

2022-10-11

Write the point slope form of the equation given (-4,-4) and slope 1/5

Bestvinajw

Beginner2022-10-12Added 15 answers

The equation of a line in point-slope form is.

$\overline{\underline{\left|{\frac{2}{2}}{y-{y}_{1}=m(x-{x}_{1})}{\frac{2}{2}}\right|}}$

where m represents the slope and $({x}_{1},{y}_{1})\phantom{\rule{1ex}{0ex}}\text{a point on the line}$

$\text{here}\phantom{\rule{1ex}{0ex}}m=\frac{1}{5}\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}({x}_{1},{y}_{1})=(-4,-4)$

Substitute these values into the equation.

$y-(-4)=\frac{1}{5}(x-(-4))$

$\Rightarrow y+4=\frac{1}{5}(x+4)\leftarrow {\phantom{\rule{1ex}{0ex}}\text{in point-slope form}}$

$\overline{\underline{\left|{\frac{2}{2}}{y-{y}_{1}=m(x-{x}_{1})}{\frac{2}{2}}\right|}}$

where m represents the slope and $({x}_{1},{y}_{1})\phantom{\rule{1ex}{0ex}}\text{a point on the line}$

$\text{here}\phantom{\rule{1ex}{0ex}}m=\frac{1}{5}\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}({x}_{1},{y}_{1})=(-4,-4)$

Substitute these values into the equation.

$y-(-4)=\frac{1}{5}(x-(-4))$

$\Rightarrow y+4=\frac{1}{5}(x+4)\leftarrow {\phantom{\rule{1ex}{0ex}}\text{in point-slope form}}$

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