Find the equation of the line perpendicular to y=11x/16 that passes through (3,−7)

Tyson Atkins

Tyson Atkins

Answered question

2022-10-14

Find the equation of the line perpendicular to y = 11 16 x that passes through (3,−7)

Answer & Explanation

cesantedz

cesantedz

Beginner2022-10-15Added 12 answers

Any straight line graph as equation y=mx+c where m is the slope or gradient and c is the y-intercept.
Furthermore, perpendicular lines have gradients whose products is −1.
So in this case, y = 11 16 x has gradient m = 11 16
So another line perpendicular to this one will have gradient - 16 11
Now substituting the point (x,y)=(3,−7) into its general equation y=mx+c yields
- 7 = ( - 16 11 ) ( 3 ) + c
from which we obtain the value for c = - 29 11
Thus the required line has equation y = - 16 11 x - 29 11

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