Write an equation of a line going through (7,1) parallel to y=-x+3

Question

flasheadita237m · Accepted Answer

Equations that are parallel have the same slope.
The standard equation of an equation is written through slope intercept form, which is y=mx+b where m is your slope and b is the y intercept
So, in the equation provided, -1 is the slope.
To write an equation when given a slope and points, you use point slope form, which is

y - y_{1} = m (x - x_{1})

y_{1}

is the y in the set of points you are given, same with

x_{1}

So,

y_{1} = 1

and

x_{2} = 7

As stated before, m is the slope, and the slope is given as -1
Plug in the numbers into the equation
y−1=−1(x−7)
Distribute -1 throughout the parenthesis
y−1=−x+7
Add 1 on both sides of the equation
y=−x+8
And there you have a equation parallel to y=−x+3

Write an equation of a line going through (7,1) parallel to y=-x+3

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