Consider the field K=Q(X1,…,Xp), where X is your nonzero solution. We want to construct a (Q-linear) map f:K->Q with some f(Xi)≠0 since the entries of A lie in Q, we'll then have Af(X)=0 with f(X) in Qp nonzero.

Jaelyn Payne

Jaelyn Payne

Answered question

2022-10-17

Consider the field K = Q ( X 1 , , X p ), where X is your nonzero solution. We want to construct a ( Q -linear) map f : K Q with some f ( X i ) 0 since the entries of A lie in Q , we'll then have A f ( X ) = 0 with f ( X ) Q p nonzero. Construct a tower of fields Q = K 0 K r = K with each K i / K i 1 either algebraic or isomorphic to K i 1 ( t ) for some purely transcendental element t. In the former case, use the nondegeneracy of the trace form. In the latter case, use the fact that the map f : K i 1 ( t ) K i 1 with f | K i 1 = id and f ( t ) = α for any fixed α K i 1 is well-defined.

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Warkallent8

Warkallent8

Beginner2022-10-18Added 16 answers

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