x^2+x+1>0

blackdivcp

blackdivcp

Answered question

2022-10-16

x 2 + x + 1 > 0

Answer & Explanation

bigfreakystargl

bigfreakystargl

Beginner2022-10-17Added 23 answers

First, find the 2 x-intercepts (real roots) by solving
f ( x ) = x 2 + x + 1 = 0
D = d^2 = b^2 - 4ac = 1 - 4 = -3.
There is no x-intercepts. Since a > 0, the parabola opens upward and is completely above the x-axis.
The inequality f(x) > 0 is always true, regardless of x.

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