Write an equation of a line passing through (2, 5), perpendicular to x−5y=−10

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Kaylee Evans · Accepted Answer

Let&#039;s first look at the the line x−5y=−10 and solve it for y so that we can put it into the slope-intercept form, the general form of which is:y=mx+b, where m= slope and b= y-intercept.      x    -    5    y    =    -    10        5    y    =    x    +    10        y    =          1      5        x    +    2  And so slope,       m    =          1      5      To find the perpendicular slope, we take the negative inverse, which gives us m=−5.To find the line passing through the point (2,5) with slope −5, we can use the point slope form, which has as a general form:      y    -          y      1        =    m          (      x      -              x        1            )       where             x      1        ,          y      1       are a point. So we have:(y−5)=−5(x−2)For comparison, let&#039;s put this into slope-intercept form:y=−5x+15

Write an equation of a line passing through (2, 5), perpendicular to x−5y=−10

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