In the process of running through an algorithm, I have derived the following systems of equations:i) 1 / 3 + 1 / 3 x 1 + 1 / 3 x 6 = x 5 ii) 1 / 2 + 1 / 4 x 6 = x 1 iii) 1 / 2 + 1 / 2 x 5 = x 6

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In the process of running through an algorithm, I have derived the following systems of equations:i)   1      /    3  +  1      /    3      x    1    +  1      /    3      x    6    =      x    5  ii)   1      /    2  +  1      /    4      x    6    =      x    1  iii)   1      /    2  +  1      /    2      x    5    =      x    6

Lintynx · Accepted Answer

we ca write  1  +      x    1    +      x    6    =  3      x    5    2  +      x    6    =  4      x    1    1  +      x    5    =  2      x    6  with       x    5    =  2      x    6    −  1 we get      x    1    −  5      x    6    =  −  4and with      x    6    =  4      x    1    −  2we obtain      x    1    −  5  (  4      x    1    −  2  )  =  −  4thus we get      x    1    =      14    19  from here we can proceed.

In the process of running through an algorithm, I have derived the following systems of equations: i) 1/3+1/3x_1+1/3x_6=x_5, ii) 1/2+1/4x_6=x1, iii) 1/2+1/2x_5=x_6

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