Find the equation of the line that passes through (−1,1) and is perpendicular to the line that passes through the following points: (−2,4),(−12,21)

cimithe4c

cimithe4c

Answered question

2022-10-25

Find the equation of the line that passes through (−1,1) and is perpendicular to the line that passes through the following points: (−2,4),(−12,21)

Answer & Explanation

driogairea1

driogairea1

Beginner2022-10-26Added 16 answers

The slope of the line passing through (−2,4) and (−12,21)
is m 1 = y 2 - y 1 x 2 - x 1 = 21 - 4 - 12 + 2 = - 17 10
The product of slopes of the pependicular lines is m 1 m 2 = - 1
m 2 = - 1 - 17 10 = 10 17 . Hence the slope of the pependicular
line is m 2 = 10 17 . Equation of line passing through (−1,1)
is y - y 1 = m 2 ( x - x 1 ) or y - 1 = 10 17 ( x + 1 ) or
17 y - 17 = 10 ( x + 1 ) or 10 x - 17 y = - 27
Equation of line is 10 x - 17 y = - 27

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