How many gallons of 20% antifreeze solution and a 10% antifreeze solution must be mixed to obtain 40 gallons of a 16% antifreeze solution?

jernplate8

jernplate8

Answered question

2020-11-22

How many gallons of 20% antifreeze solution and a 10% antifreeze solution must be mixed to obtain 40 gallons of a 16% antifreeze solution?

Answer & Explanation

pierretteA

pierretteA

Skilled2020-11-23Added 102 answers

Let x be the number of gallons of 20% antifreeze solution so that 40−x is the number of gallons of 10% antifreeze solution.
In terms of percentage,
0.20x+0.10(40−x)=0.16(40)
Solve for x:
0.20x+4−0.10x=6.4
0.10x+4=6.4
0.10x=2.4
x=2.40.10
x=24
So, you need to mix 24 gallons of 20% antifreeze solution and 16 gallons of 10% antifreeze solution.
Jeffrey Jordon

Jeffrey Jordon

Expert2021-08-10Added 2605 answers

Hope my video will help you

Jeffrey Jordon

Jeffrey Jordon

Expert2021-10-09Added 2605 answers

Answer is given below (on video)

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