We are given: ²25p²−10p=2 Solve by completing the square. First, we write the equation in the form ²x²−10x=c. Divide both sides by 25: ²p²−25p=225 Complete the square by adding (b2)2 on both sides. Here, b=−(25) so we add (−252)2=125 to both sides: ²p²−25p+125=225+125 (p−(15))2=325 Take the square root of both sides: p−(15)=±35 Add 1/5 to both sides: p=15±35 p=1±35

"²25p²−10p=2" was answered by our experts

High School
Algebra
Algebra I
Quadratic function and equation

Emily-Jane Bray

Answered question

2021-02-25

25 p ² - 10 p = 2

Answer & Explanation

Bentley Leach

Skilled2021-02-26Added 109 answers

We are given:

25 p ² - 10 p = 2

Solve by completing the square. First, we write the equation in the form

x ² - 10 x = c

. Divide both sides by 25:

p ² - \frac{2}{5} p = \frac{2}{25}

Complete the square by adding

{(\frac{b}{2})}^{2}

on both sides. Here,

b = - (\frac{2}{5})

so we add

{(\frac{- \frac{2}{5}}{2})}^{2} = \frac{1}{25}

to both sides:

p ² - \frac{2}{5} p + \frac{1}{25} = \frac{2}{25} + \frac{1}{25}

{(p - (\frac{1}{5}))}^{2} = \frac{3}{25}

Take the square root of both sides:

p - (\frac{1}{5}) = \pm \frac{\sqrt{3}}{5}

Add 1/5 to both sides:

p = \frac{1}{5} \pm \frac{\sqrt{3}}{5}

p = \frac{1 \pm \sqrt{3}}{5}

Jeffrey Jordon

Expert2021-08-10Added 2605 answers

Answer is given below (on video)

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