Quadratic Function for braking distance. Car Velocity v (km/hr) : a series of non zero positive values. Car Brake distance d (meter) : also a series of non zero positive values. The problem asks why a quadratic equation is suitable to find the relationship between v and d?

Taniya Melton

Taniya Melton

Answered question

2022-10-30

Quadratic Function for braking distance
I have this question about finding a quadratic equation:
Car Velocity v (km/hr) : a series of non zero positive values
Car Brake distance d (meter) : also a series of non zero positive values.
The problem asks why a quadratic equation is suitable to find the relationship between v and d?
The problem also asks if d = a v 2 + b v + c where a, b and c are constants, find the function.
Here are v values (km/hr) : 20, 30, 40, 50, 60, 70, 80, 90, 100 Here are d values (meters) : 15, 20, 25, 40, 50, 65, 80, 100, 115
My observation so far: I have seen a range of x values including zero value and corresponding y values being converted to quadratic equation using 1st difference and 2nd difference of y values. That solution may not work all the time, especially when I don't have zero value for x.
Secondly, I think the problem lacks key information such as deceleration, response time.

Answer & Explanation

snowman8842

snowman8842

Beginner2022-10-31Added 12 answers

Step 1
This is just a quick answer, but you have set of values ( v i , d i ) and want to fit it to an equation of the form d ( v ) = a v 2 + b v + c. Each term will have an associated error r i = d ( v i ) d i . You want to minimise this for all terms, in other words:
min ( r i ) 2
To do this we can set up a system, say:
S = r i 2 = ( a v i 2 + b v i + c d i ) 2
and to find the minimas we want all of the partial derivatives equal to zero:
0 = S a = 2 v i 2 ( a v i 2 + b v i + c d i )
0 = S b = . . .
0 = S c = . . .
Step 2
Hopefully you get the picture. Now rearrange all of said equations, I will show the top one:
a v i 4 + b v i 3 + c v i 2 = d i v i 2
You now have a value mutliplied by a,b,c which you can work out and using all 3 possible equations get something of the form:
[ α β γ δ ϵ ζ η θ ι ] ( a b c ) = ( κ λ μ )
you will know all of the greek letters' values so now just find the inverse of the matrix (online calculators for this exist) and you now have values for a,b,c

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