I have two functions and want to find out in which points they intersect. f(x)=-3x^3-3x^2+Ax. g(x)=x^3+x^2-6x.

snaketao0g

snaketao0g

Answered question

2022-10-30

I have two functions and want to find out in which points they intersect
f ( x ) = 3 x 3 3 x 2 + A x
g ( x ) = x 3 + x 2 6 x
I know that parameter should be A = 18, but it was just my guess. What I want to as you for is the process how to find it.
I know that I must start by f ( x ) = g ( x ) and then f ( x ) g ( x ) = 0 and so on, but I am stuck with quadratic equation with parameter.

Answer & Explanation

Messiah Trevino

Messiah Trevino

Beginner2022-10-31Added 18 answers

Step 1
y = f ( x ) and y = g ( x ) intersect where f ( x ) = g ( x ). Here that is 3 x 3 3 x 2 + A x = x 3 + x 2 6 x. The first thing I see is that x ( 3 x 2 3 x + A ) = x ( x 2 + x 6 ) so x = 0 is one solution. If x 0 then we can divide both sides by x to get 3 x 2 3 x + A = x 2 + x 6. We can write that as 4 x 2 + 4 x ( A + 6 ) = 0. That is a quadratic equation which has roots x = 4 ± 16 4 ( 4 ) ( A + 6 ) 2 ( 4 ) = 4 ± 4 1 A 6 8
Step 2
Now the question of the number of real roots depends upon the value of A 5. If A = 5 then A 5 = 0 so the quadratic equation has one real solution and the graphs cross twice. If A < 5 so A 5 > 0 the quadratic equation has two real solutions and the graphs cross three times. If A > 5 so A 5 < 0 so the quadratic equation has no real solutions and the graphs cross only once.

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