Write the equation of line passes through (4, -5), and is perpendicular to 2x-5y= -10

unabuenanuevasld

unabuenanuevasld

Answered question

2022-11-10

Write the equation of line passes through (4, -5), and is perpendicular to 2x-5y= -10

Answer & Explanation

Incampo5in

Incampo5in

Beginner2022-11-11Added 10 answers

Let us write the equation of line 2x-5y=-10# in slope intercept form i.e.
−5y=−2x−10 or y = 2 5 x + 2
i.e. its slope is 2 5 . Hence the slope of a line perpendicular to it is - 1 2 5 = - 5 2 .
Now equation of a line passing through appoint ( x 1 , y 1 ) and having a slope m is given by
( y - y 1 ) = m ( x - x 1 ) and
so the equationn of line passing through (4,−5) and having a slope of - 5 2 is
( y - ( - 5 ) ) = - 5 2 ( x - 4 ) or
y + 5 = - 5 2 x + 5 × 4 2 or
y + 5 = - 5 2 x + 10
2y+10=−5x+20 or 5x+2y=10

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