Find the equation of the line perpendicular to y=9x/10 that passes through (−1,5)

Simone Watts

Simone Watts

Answered question

2022-11-09

Find the equation of the line perpendicular to y=9x/10 that passes through (−1,5)

Answer & Explanation

takwerkyo0

takwerkyo0

Beginner2022-11-10Added 17 answers

A straight line graph of form y=mx+c has gradient m and y-intercept c.
Perpendicular lines have gradients whose product is −1.
So the gradient of the given line is 9 10 and so a line perpendicular to this line would have gradient - 10 9 .
We may now substitute the point (x,y)=(−1,5) into the general equation of the required line to solve :
y = m x + c
5 = - 10 9 ( - 1 ) + c
c = 35 9
Thus the required line has equation y = - 10 9 x + 35 9

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