Calculate the coordinates of the intersections point between a straight line with a given slope and a quadratic function, so that you only receive one intersection instead of the normal two or none. I am given the slope gradient m and the quadratic equation. In this example its y=x^2+3x-2, m=1

fabler107

fabler107

Answered question

2022-11-14

How do I get the tangent coordinates if I am given the quadratic function and the slope(gradient)
Calculate the coordinates of the intersections point between a straight line with a given slope and a quadratic function, so that you only receive one intersection instead of the normal two or none. I am given the slope gradient m and the quadratic equation.
In this example its
y = x 2 + 3 x 2 , m = 1

Answer & Explanation

martinmommy26nv8

martinmommy26nv8

Beginner2022-11-15Added 16 answers

Step 1
First, find the derivative of y = x 2 + 3 x 2.
y = 2 x + 3
Step 2
Now set 2 x + 3 = m = 1.
Solve for x to find the x coordinate of the point you need.
Then place your solution for x into the equation y = x 2 + 3 x 2 to find the y-coordinate.
Jenny Roberson

Jenny Roberson

Beginner2022-11-16Added 4 answers

Step 1
Let the equation of straight line be y = m x + c. Solve for the intersection:
m x + c = x 2 + 3 x 2
You get a quadratic in x.
x 2 + ( 3 m ) x ( 2 + c ) = 0
Step 2
To have only one intersection point, there should be only value of x satisfying the above equation. So you make the discriminant of the above equation zero.
So now your x is simply ( m 3 ) / 2
You know the value of m, so you know x, then you can find y to know the intersection point.

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