Find an equation of a line containing the point (-2, 2), and perpendicular to the line 2(y + 1) = x

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Eynardfb0 · Accepted Answer

First we have to transform the given equation to form y=ax+b :      2          (      y      +      1      )        =    x        2    y    +    2    =    x        2    y    =    x    -    2        y    =          1      2        x    -    1  Now we can write the equation of a line perpendicular to the given one.Two lines are perpendicular if and only if product of their slopes is −1:            1      2        ⋅    m    =    -    1  m=−2So the line we are looking for has equation:y=−2x+bNow we have to calculate the value of b for which point (−2;2) belongs to the line:To do this we have to put the point&#039;s coordinates as x and y:2=−2(−2)+b2=4+bb=−2Finally the line perpendicular to 2(y+1)=x passing rhrough (−2,2) isy=−2x−2

Find an equation of a line containing the point (-2, 2), and perpendicular to the line 2(y + 1) = x

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