How many functions respect the equation 3f(f(x))−7f(x)+2x=0

inurbandojoa

inurbandojoa

Answered question

2022-11-14

How many functions respect the equation 3 f ( f ( x ) ) 7 f ( x ) + 2 x = 0

Answer & Explanation

motylowceyvy

motylowceyvy

Beginner2022-11-15Added 19 answers

Fix x and let a n = f n ( x ) (n-th iteration of f). Then we have
3 a n + 1 7 a n + 2 a n 1 = 0
Solving this recurrence we get
a n = a 2 n + b 1 3 n
for some a,b. Since a 0 = x and a 1 = f ( x ) we have x = a + b and f ( x ) = 2 a + b / 3. Solving this on a,b we get
a = 3 f ( x ) x 5 a n d b = 6 x 3 f ( x ) 5
Since x,f(x) are integers we have a = c / 5 and b = d / 5 for some integers c,d. So we have
5 a n c 2 n = d 1 3 n 3 n d n N
which is possible only iff d=0 and so b=0. Thus we have f ( x ) = 2 x
MMDCCC50m

MMDCCC50m

Beginner2022-11-16Added 5 answers

Consider g ( x ) = f ( x ) 2 x. If f : Z Z then g : Z Z
3 f ( f ( x ) ) = 7 f ( x ) 2 x 3 g ( f ( x ) ) = 3 f ( f ( x ) ) 6 f ( x ) = f ( x ) 2 x = g ( x ) g ( f ( x ) ) = g ( x ) 3
Suppose that g ( x 1 ) 0 for some x 1 Z . Consider infinite sequence ( a n ), such that a i = | g ( b i ) | , b 1 = x 1 , b i + 1 = f ( x i ). Then a i + 1 = a i 3 and a i Z . Sequence ( a n ) is decreasing, positive and integer. That is impossible. Contradiction.
Then g ( x ) = 0 for all x Z . Then f ( x ) = 2 x is the only function Z Z to satisfy the given equation.

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