How do you find a_25 given a_n=(−1)^n(3n−2)?

Madison Costa

Madison Costa

Answered question

2022-11-15

How do you find a 25 given a n = ( - 1 ) n ( 3 n - 2 ) ?

Answer & Explanation

x0xkatiex0xz6u

x0xkatiex0xz6u

Beginner2022-11-16Added 11 answers

Substitute 25 for every occurrence of n in a n :
a n = ( - 1 ) n ( 3 n - 2 ) becomes:
a 25 = ( - 1 ) 25 ( ( 3 25 ) - 2 )
−1even power = 1 ( - 1 2 = 1 ; - 1 4 = 1 )
−1odd power = -1 ( - 1 3 = - 1 ; - 1 5 = 1 )
Therefore: - 1 25 = - 1
So we can rewrite as:
a 25 = - 1 ( ( 3 25 ) - 2 )
a 25 = - 1 ( 75 - 2 )
a 25 = - 73

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?