Show that the set of irrational numbers is dense in R using definition of Closure

ajakanvao

ajakanvao

Answered question

2022-11-18

Show that the set of irrational numbers is dense in R using definition of Closure

Answer & Explanation

Samsonitew7b

Samsonitew7b

Beginner2022-11-19Added 15 answers

You can use that "rational plus irrational" is irrational. So you could form
q + 2 n ,         n N .
All numbers in this sequence are irrational, and the sequence converges to q.
That Q has empty interior follows directly from the above. Given q Q and any interval I = ( q ε , q + ε ), by the above there are irrationals in I. So I Q , which implies that Q has empty interior.
Kameron Wang

Kameron Wang

Beginner2022-11-20Added 4 answers

Hint: a n = 1 2 n is a sequence in Q c converging to 0. For any other r Q , just shift the sequence by r.. that is, b n = a n + r is a sequence in Q c converging to r...

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