x^4-12x^2+11<0

pin1ta4r3k7b

pin1ta4r3k7b

Answered question

2022-11-17

x 4 - 12 x 2 + 11 < 0

Answer & Explanation

lavarcar2d2

lavarcar2d2

Beginner2022-11-18Added 18 answers

Then we first solve for u 2 - 12 u + 11 = 0
( u - 1 ) ( u - 12 ) = 0 u = 1 or u = 12

There are now four solutions:
x = ± 1 = ± 1 or x = ± 12 = ± 2 3

We'll have to examine what happens between and outside those points.
If we take any value between - 2 3 and - 1 the outcome will be negative, between - 1 and + 1 it's positive, and between + 1 and + 2 3 it will be negative again.
< - 2 3 and > + 2 3 the outcome will be positive.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?