Write the first five terms of the arithmetic sequence given a_8=26,a_12=42

vedentst9i

vedentst9i

Answered question

2022-11-19

Write the first five terms of the arithmetic sequence given a 8 = 26 , a 12 = 42

Answer & Explanation

Camden Stanton

Camden Stanton

Beginner2022-11-20Added 14 answers

The general term of an arithmetic sequence is given by the formula:
a n = a + d ( n - 1 )
where a is the initial term and d the common difference.
Given a 8 = 26 and a 12 = 42 , we find:
16 = 42 - 26
16 = a 12 - a 8
16 = ( a + 11 d ) - ( a + 7 d )
16 = 4 d
Hence d=4
Then:
26 = a 8 = a + 7 d = a + 28
Hence a=−2
So the first five terms of the sequence are:
−2,2,6,10,14

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