Identify the 42nd term of an arithmetic sequence where a_1=12 and a_27=66.

Scarlet Marshall

Scarlet Marshall

Answered question

2022-11-26

Identify the 42nd term of an arithmetic sequence where a 1 = 12 and a 7 = 66.

Answer & Explanation

Lilyana Simon

Lilyana Simon

Beginner2022-11-27Added 7 answers

a n = a 1 + ( n 1 ) d a 1 = 12 , n = 27 ,   a n d a 27 = 66 a 27 = a 1 + ( 27 1 ) d 66 = 12 + 26 × d 26 × d = 66 + 12 d = 3 a 42 = 12 + 41 × 3 a 42 = 111
the 42nd term of the given arithmetic sequence is 111

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