How to sketch the graph of y = arccos ( x 4 ) ∈ [ 0 , π ] ?

Question

How to sketch the graph of       y    =          arccos              (                  x          4                )              ∈          [      0      ,      π      ]      ?

bbiillyyh3l · Accepted Answer

y    =          arccos              (                  x          4                )              ∈          [      0      ,      π      ]      The graph is constrained to look this way.Inversely,       x    =    4          cos      y        ∈          [      -      4      ,      4      ]       and the waveform, in the y-direction, is understandable. Yet, the graph is blocked, and the the y- periodicity becomes incognito.See graph.graph{(y-arccos (x/4))=0}For contrast, see the wholesome inverse graph of       x    =    4          sin      y       that is identical with the piecewise wholesome       y    =                  (        cos        )                    -        1                    (              x        4            )        =    k    π    +                  (        -        1        )            k              arcsin              (                  x          4                )              ,        k    =    0    ,    ±    1    ,    ±    2    ,    ±    3    ,    ...  : graph{(x-4 cos y)(x-4 +0.001y) (x+4 +0.001y) = 0[ -5 5 -20 20]}

How to sketch the graph of f(x)=arccos(x/4)?

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