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chillywilly12a

Answered question

2021-06-15

Find derivatives for the functions. Assume a, b, c, and k are constants. $s (t) = 6 t^{- 2} + 3 t^{3} - 4 t^{\frac{1}{2}}$

Answer & Explanation

avortarF

Skilled2021-06-16Added 113 answers

Find derivative of given function:

s^{'} (t) =^{1} {(6 t^{- 2})}^{'} + {(3 t^{3})}^{'} - {(4 t^{\frac{1}{2}})}^{'}

=^{2} 6 \dot{- 2 t^{3}} + 3 \dot{3} t^{2} - 4 \dot{\frac{1}{2}} t^{- \frac{1}{2}}

= - 12 t^{- 3} + 9 t^{2} - 2 t^{- \frac{1}{2}}

Rules used:
(1) Derivative of sum
(2) Power rule

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