Find the integer a such that a≡−15(mod27) and −26≤a≤0

Division algorithm Let a be an integer and d a positive integer. Then there are unique q and r with 0 q=a÷d r=a mod d a≡−15(mod27) and −26≤a≤0 Since -15 is between -26 and 0: a=−15

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Calculus and Analysis
Differential Calculus
Analyzing functions

postillan4

Answered question

2021-09-13

Find the integer a such that
$a \equiv - 15 (mod 27) and - 26 \leq a \leq 0$

Answer & Explanation

Leonard Stokes

Skilled2021-09-14Added 98 answers

Division algorithm Let a be an integer and d a positive integer. Then there are unique q and r with 0 $q = a \div d$
$r = a mod d$
$a \equiv - 15 (mod 27) and - 26 \leq a \leq 0$ Since -15 is between -26 and 0: $a = - 15$

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