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beljuA

Answered question

2021-09-20

Find the derivatives.

g (t) = e^{\sin t} \cos^{4} t

Answer & Explanation

Adnaan Franks

Skilled2021-09-21Added 92 answers

g (t) = e^{\sin t} \cos^{4} t :

Finding derivative of the function:

\Rightarrow g^{'} (t) = \frac{d}{d t} (e^{\sin t} \cos^{4} t)

\Rightarrow g^{'} (t) = e^{\sin t} \cos^{4} t \times \cos t + e^{\sin t} \cdot 4 \cos^{3} t \times - \sin t

\Rightarrow g^{'} (t) = e^{\sin t} \cos^{5} t - 4 e^{\sin t} \sin t \cos^{3} t

Jeffrey Jordon

Expert2022-02-01Added 2605 answers

Answer is given below (on video)

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