The following questions are about the function f(x,y)=x^{2}e^{2xy}.

Mylo O'Moore

Mylo O'Moore

Answered question

2021-10-08

The following questions are about the function f(x,y)=x2e2xy.
Find the partial derivatives, fx(x,y) and fy(x,y).

Answer & Explanation

Arnold Odonnell

Arnold Odonnell

Skilled2021-10-09Added 109 answers

Step 1
If f(x,y) is a function of two variables x and y, then
fx(x,y)=fx
fy(x,y)=fy
The equation of the tangent plane of function f at the point (x0,y0) is
z=f(x0,y0)+fx(x0,y0)(xx0)+fy(x0,y0)(yy0)
Step 2
The given function is
f(x,y)=x2e2xy
Differentiate the given function partially with respect to x.
fx(x,y)=x2x(e2xy)+e2xyxx2
=x2(2ye2xy)+e2xy(2x)
=2xe2xy(xy+1)
Differentiate the given function partially with respect to y.
fy(x,y)=x2y(e2xy)
=x2(2xe2xy)
=2x3e2xy
Jeffrey Jordon

Jeffrey Jordon

Expert2022-08-15Added 2605 answers

Answer is given below (on video)

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