Step 1 y=exsin⁡h(x) Apply product rule for taking derivative y=uv y‘=u‘v+v‘(u) derivative of sin⁡h(x) is cos⁡h(x) Step 2 y=exsin⁡h(x) y‘=exsin⁡h(x)+excos⁡h(x) y‘=ex(sin⁡h(x)+cos⁡h(x))

Best solutions to - "y=exsin⁡h(x)"

Jessica Scott

Answered question

2021-11-21

y = e^{x} \sin h (x)

Answer & Explanation

Ancessitere

Beginner2021-11-22Added 17 answers

Step 1

y = e^{x} \sin h (x)

Apply product rule for taking derivative

y = u v

y ‘ = u ‘ v + v ‘ (u)

derivative of

\sin h (x)

\cos h (x)

Step 2

y = e^{x} \sin h (x)

y ‘ = e^{x} \sin h (x) + e^{x} \cos h (x)

y ‘ = e^{x} (\sin h (x) + \cos h (x))

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