Step1y=exsin⁡h(x)Apply product rule for taking derivativey=uvy′=u′v+v′(u)derivative of sin⁡h(x) is cos⁡h(x)Step2y=exsin⁡h(x)y′=exsin⁡h(x)+excos⁡h(x)y′=ex(sin⁡h(x)+cos⁡h(x))

Find out the answer to "y=exsin⁡hx"

Aufopferaq

Answered question

2021-11-28

y = e^{x} \sin h x

Answer & Explanation

Florence Pittman

Beginner2021-11-29Added 15 answers

Step1

y = e^{x} \sin h (x)

Apply product rule for taking derivative

y = u v

y^{'} = u^{'} v + v^{'} (u)

derivative of

\sin h (x)

\cos h (x)

Step2

y = e^{x} \sin h (x)

y^{'} = e^{x} \sin h (x) + e^{x} \cos h (x)

y^{'} = e^{x} (\sin h (x) + \cos h (x))

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