"∫2e−5xdx ∫e8xdx" was answered by our experts

osi4a2nxk

Answered question

2021-11-26

\int 2 e^{- 5 x} d x

\int e^{8 x} d x

Answer & Explanation

Richard Cheatham

Beginner2021-11-27Added 16 answers

Step 1

I = \int 2 e^{- 5 x} d x

- 5 x = t

- 5 d x = d x

I = 2 (\frac{- 1}{5}) \int e^{t} d t

I = \frac{- 2}{5} \int e^{t} d t

I = \frac{- 2}{5} e^{t} + c

I = \frac{- 2}{5} e^{- 5 x} + c

Step 2

I = \int e^{8 x} d x

8 x = t

8 d x = d t

I = \frac{1}{8} \int e^{t} d t

I = \frac{1}{8} e^{t} + c

I = \frac{1}{8} e^{8 x} + c

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