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Baublysiz

Answered question

2021-12-04

Calculating derivatives Find the derivative of the following functions.

y = \sec x \tan x

Answer & Explanation

Ancessitere

Beginner2021-12-05Added 17 answers

Step 1
Given

y = \sec x \tan x

Step 2
Derivative

\frac{d y}{d x} = \frac{d}{d x} (\sec x \tan x)

Since

\frac{d}{d x} (U V) = U \frac{d v}{d x} + v \frac{d u}{d x}

\frac{d y}{d x} = \sec x \frac{d}{d x} (\tan x) + \tan x \frac{d}{d x} (\sec x)

\frac{d y}{d x} = \sec x (\sec^{2} x) + (\tan x) (\sec x \tan x)

\frac{d y}{d x} = \sec^{3} x + \sec x \tan^{2} x

\frac{d y}{d x} = \sec x (\sec^{2} x + \tan^{2} x)

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