Find the derivatives of the functions y=(\theta 2+\sec \theta +

Sapewa

Sapewa

Answered question

2021-12-06

Find the derivatives of the functions y=(θ2+secθ+1)3

Answer & Explanation

David Clayton

David Clayton

Beginner2021-12-07Added 36 answers

Given information:
The function is y=(θ2+secθ+1)3.
Calculation:
Find the derivative of the function y=(θ2+secθ+1)3 with respect to \theta as follows:
dydθ=ddθ((θ2+secθ+1)3)
=3(θ2+secθ+1)2(2θ+secθtanθ)
Therefore, the derivative of the function is dydθ=3(θ2+secθ+1)2(2θ+secθtanθ)

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