Get the solution to "Derivatives involving sec⁡x and csc⁡x Find the derivative" - Plainmath

namenerk

Answered question

2021-12-07

Derivatives involving

\sec x and \csc x

Find the derivative of

y = \sec x \csc x

.

Answer & Explanation

Jeffery Autrey

Beginner2021-12-08Added 35 answers

Step 1
Find the derivative of

y = \sec x \csc x

.
Step 2

y^{'} = \frac{d}{d x} (\sec x \csc x)

= \frac{d}{d x} (2 \csc 2 x)

= - 2 \cot 2 x \csc 2 x \frac{d}{d x} (2 x)

= - 2 \cot 2 x \csc 2 x (2)

= - 4 \cot 2 x \csc 2 x

Hence, the derivative of

y = \sec x \csc x i s - 4 \cot 2 x \csc 2 x

.

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