Find the derivatives of the functions y = (1 -

Walter Clyburn

Walter Clyburn

Answered question

2021-12-10

Find the derivatives of the functions y=(1t)(1+t2)1

Answer & Explanation

Natalie Yamamoto

Natalie Yamamoto

Beginner2021-12-11Added 22 answers

Given,
y=(1t)(1+t2)1
y=1+t2tt31
y=t2tt3
Now differentiating with respect to t, we get
dydt=2t13t2   [d(xn)dx=nxn1]

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