Resolved: "Find the first and second derivatives of the..." - Plainmath

obrozenecy6

Answered question

2021-12-06

Find the first and second derivatives of the function

G (t) = 2 \cos t - 3 \sin

Answer & Explanation

Raymond Foley

Beginner2021-12-07Added 39 answers

Given:
The given equation is

G (t) = 2 \cos t - 3 \sin

Calculation:
First derivative:

G^{'} (t) = \frac{d}{d t} (2 \cos t - 3 \sin t)

= 2 \frac{d}{d t} (\cos t) - 3 \frac{d}{d t} (\sin t)

= - 2 \sin t - 3 \cos

Step 3
Second derivative:

G^{″} (t) = \frac{d}{d t} (- 2 \sin t - 3 \cos t)

= - 2 \frac{d}{d t} (\sin t) - 3 \frac{d}{d t} (\cos t)

= - 2 \cos t + 3 \sin

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