Evaluating \lim_{x \to 0} \frac{x^2-\ln (\cos x)}{x}

trefoniu1

trefoniu1

Answered question

2022-01-26

Evaluating limx0x2ln(cosx)x

Answer & Explanation

euromillionsna

euromillionsna

Beginner2022-01-27Added 16 answers

Without L'Hopital: let f(x)=x2ln(cosx).
Then
limx0x2ln(cosx)x=
=limx0f(x)f(0)x0=f(0)=0
Flickkorbma

Flickkorbma

Beginner2022-01-28Added 17 answers

For the highlighted question use LHopitals Rule. Since lim2x+tanx1=0 the answer is 0.

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