Find the derivative of ln &#x2061;<!-- ⁡

Aedan Tyler

Aedan Tyler

Answered question

2022-05-13

Find the derivative of ln ( 2 + 3 + 6 x ).

Answer & Explanation

hospitaliapbury

hospitaliapbury

Beginner2022-05-14Added 25 answers

Use axn=axn to rewrite 3+6x as (3+6x)12.

ddx[ln(2+(3+6x)12)]

Differentiate using the chain rule, which states that ddx[f(g(x))] is f(g(x))g(x) where f(x)=ln(x) and g(x)=2+(3+6x)12.

12+(3+6x)12ddx[2+(3+6x)12]

Differentiate.

12+(3+6x)12ddx[(3+6x)12]

Differentiate using the chain rule, which states that ddx[f(g(x))] is f(g(x))g(x) where f(x)=x12 and g(x)=3+6x.

12+(3+6x)12(12(3+6x)12-1ddx[3+6x])

To write -1 as a fraction with a common denominator, multiply by 22.

12+(3+6x)12(12(3+6x)12-122ddx[3+6x])

Combine -1 and 22.

12+(3+6x)12(12(3+6x)12+-122ddx[3+6x])

Combine the numerators over the common denominator.

12+(3+6x)12(12(3+6x)1-122ddx[3+6x])

Simplify the numerator.

12+(3+6x)12(12(3+6x)-12ddx[3+6x])

Combine fractions.

12(3+6x)12(2+(3+6x)12)ddx[3+6x]

By the Sum Rule, the derivative of 3+6x with respect to x is ddx[3]+ddx[6x].

12(3+6x)12(2+(3+6x)12)(ddx[3]+ddx[6x])

Since 3 is constant with respect to x, the derivative of 3 with respect to x is 0.

12(3+6x)12(2+(3+6x)12)(0+ddx[6x])

Add 0 and ddx[6x].

12(3+6x)12(2+(3+6x)12)ddx[6x]

Since 6 is constant with respect to x, the derivative of 6x with respect to x is 6ddx[x].

12(3+6x)12(2+(3+6x)12)(6ddx[x])

Simplify terms.

232(3+6x)12(2+(3+6x)12)ddx[x]

Cancel the common factors.

3(3+6x)12(2+(3+6x)12)ddx[x]

Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=1.

3(3+6x)12(2+(3+6x)12)1

Multiply 3(3+6x)12(2+(3+6x)12) by 1.

3(3+6x)12(2+(3+6x)12)

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